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寫(xiě)一個(gè) Python 程序，求 10 個(gè)數(shù)的和，跳過(guò)負(fù)數(shù)。在這個(gè) Python 示例中，for 循環(huán)范圍允許輸入 10 個(gè)數(shù)字，if 條件檢查是否有負(fù)數(shù)。如果為真，continue 語(yǔ)句將跳過(guò)該數(shù)字，不將其添加到 posSum 變量中。

posSum = 0

print("Please Enter 10 Numbersto Find Positive Sum\n")
for i in range(1, 11):
    num = int(input("Number %d = " %i))

    if num < 0:
        continue

    posSum = posSum + num

print("The Sum of 10 Numbers by Skipping Negative Numbers = ", posSum)

這個(gè) Python 程序找到 10 個(gè)正數(shù)的和，并使用 while 循環(huán)跳過(guò)負(fù)數(shù)。

posSum = 0

print("Please Enter 10 Numbersto Find Positive Sum\n")
i = 1
while(i <= 10):
    num = int(input("Number %d = " %i))

    if num < 0:
        i = i + 1
        continue

    posSum = posSum + num
    i = i + 1

print("The Sum of 10 Numbers by Skipping Negative Numbers = ", posSum)

Please Enter 10 Numbersto Find Positive Sum

Number 1 = 10
Number 2 = -12
Number 3 = 15
Number 4 = -24
Number 5 = 100
Number 6 = -90
Number 7 = 120
Number 8 = -34
Number 9 = 80
Number 10 = 70
The Sum of 10 Numbers by Skipping Negative Numbers =  395

本文標(biāo)題：Python程序：計(jì)算10個(gè)數(shù)的和并跳過(guò)負(fù)數(shù)
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